In the following state whether $\mathrm{A = B}$ or not :
$A = \{ 2,4,6,8,10\} ;B = \{ x:x$ is positiveeven integer and $x\, \le \,10\} $
In the following state whether $\mathrm{A = B}$ or not :
$A = \{ 2,4,6,8,10\} ;B = \{ x:x$ is positiveeven integer and $x\, \le \,10\} $
$A=\{2,4,6,8,10\}$
$B = \{ x:x{\rm{ }}$ is a positive even integer and $x\, \le \,10\} $
$=\{2,4,6,8,10\}$
$\therefore A=B$
Similar Questions
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Let $S=\{1,2,3, \ldots, 40)$ and let $A$ be a subset of $S$ such that no two elements in $A$ have their sum divisible by 5 . What is the maximum number of elements possible in $A$ ?
Let $S=\{1,2,3, \ldots, 40)$ and let $A$ be a subset of $S$ such that no two elements in $A$ have their sum divisible by 5 . What is the maximum number of elements possible in $A$ ?
- [KVPY 2012]
Which of the following are sets ? Justify your answer.
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$\{ \{ 3,4\} \} \subset A$
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$\{ \{ 3,4\} \} \subset A$
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