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8.Mechanical Properties of Solids
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In the given figure, if the dimensions of the two wires are same but materials are different, then Young's modulus is ........

A
More for $A$ than $B$
B
More for $B$ than $A$
C
Equal for $A$ and $B$
D
None of these
Solution

(a)
At same value of load
$A$ has less elongation than $B \quad \ldots (1)$
$\frac{F L}{A Y}=\Delta L$ $\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { – Load is also taken same }\end{array}\right\}$
So $\frac{1}{Y} \propto \Delta L \quad \ldots (2)$
Using conditions $(1)$ and $(2)$
We can say
$Y_A > Y_B$ $\{$ Young's modulus of $A$ greater than $B\}$
Standard 11
Physics
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