8.Mechanical Properties of Solids
medium

In the given figure, if the dimensions of the two wires are same but materials are different, then Young's modulus is ........

A

More for $A$ than $B$

B

More for $B$ than $A$

C

Equal for $A$ and $B$

D

None of these

Solution

(a)

At same value of load

$A$ has less elongation than $B \quad \ldots (1)$

$\frac{F L}{A Y}=\Delta L$    $\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { – Load is also taken same }\end{array}\right\}$

So $\frac{1}{Y} \propto \Delta L \quad \ldots (2)$

Using conditions $(1)$ and $(2)$

We can say

$Y_A > Y_B$    $\{$ Young's modulus of $A$ greater than $B\}$

Standard 11
Physics

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