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7.Alternating Current
medium
In the given figure, the current amplitude is
A
$\sqrt {\frac{{5V_0^2}}{{4\left( {{\omega ^2}{L^2} + {R^2}} \right)}}} $
B
$\frac{{{v_0}}}{{\sqrt {4\left( {{\omega ^2}{L^2} + {R^2}} \right)} }}$
C
$\frac{{\sqrt 5 {v_0}}}{{2\sqrt {{\omega ^2}{L^2} - {R^2}} }}$
D
$\frac{{\sqrt 5 {v_0}}}{{2\sqrt {{R^2} - {\omega ^2}{L^2}} }}$
Solution
$V_{e q}=\sqrt{V_{0}^{2}+\left(\frac{V_{0}}{2}\right)^{2}}$
$\mathrm{R}_{\mathrm{eq}}=\sqrt{(\omega \mathrm{L})^{2}+\mathrm{R}^{2}}$
Standard 12
Physics
