In the molecular orbital diagram for the molecular ion, $N_2^ + $ , the number of electrons in the ${\sigma _{2p}}$ molecular orbital is
$0$
$2$
$3$
$1$
Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )
The bond order is maximum in
Compare the relative stability of the following species and indicate the magnetic properties : ${{\rm{O}}_2}{\rm{,O}}_2^ + ,{\rm{O}}_2^ - $ (super oxide); ${\rm{O}}_2^{2 - }$ (Peroxide)
The difference in energy between the molecular orbital formed and the combining atomic orbitals is called
According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $O_2^ + $