In the molecular orbital diagram for the molecular ion, $N_2^ + $ , the number of electrons in the ${\sigma _{2p}}$ molecular orbital is

 

  • [JEE MAIN 2018]
  • A

    $0$

  • B

    $2$

  • C

    $3$

  • D

    $1$

Similar Questions

Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )

  • [IIT 2017]

The bond order is maximum in

  • [AIIMS 1985]

Compare the relative stability of the following species and indicate the magnetic properties : ${{\rm{O}}_2}{\rm{,O}}_2^ + ,{\rm{O}}_2^ - $ (super oxide); ${\rm{O}}_2^{2 - }$ (Peroxide)

The difference in energy between the molecular orbital formed and the combining atomic orbitals is called

According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $O_2^ + $

  • [IIT 2004]