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4.Chemical Bonding and Molecular Structure
easy
In the process, $O_2^ + \to O_2^{ + 2} + e^-$ the electron lost is from
A
Bonding $\pi-$ orbital
B
Antibonding $\pi-$ orbital
C
$2{p_z}$ orbital
D
$2{p_x}$ orbital
Solution
(b) Electron lost from antibonding $\pi$ orbital.
Standard 11
Chemistry
Similar Questions
Match List$-I$ with List$-II.$
| List$-I$ | List$-II$ |
| $(a)$ $Ne _{2}$ | $(i)$ $1$ |
| $(b)$ $N _{2}$ | $(ii)$ $2$ |
| $(c)$ $F _{2}$ | $(iii)$ $0$ |
| $(d)$ $O _{2}$ | $(iv)$ $3$ |
Choose the correct answer from the options given below:
