In setup shown, a 200, N block is supported in equilibrium with help of strings and

English

Gujarati

Hindi

4-1.Newton's Laws of Motion

medium

In the setup shown, a $200\, N$ block is supported in equilibrium with the help of strings and a spring. A point $O$, the strings knotted. Extension in the spring is $4\, cm$. Force constant of the spring is closest to ............ $N/m$ $[g = 10\, m/s^2]$

A

$30 $

B

$2500 $

C

$3000$

D

$4000 $

Solution

In equilibrium Acc to Lami's thearum

$\frac{200}{\sin (180-90)}=\frac{\mathrm{T}_{1}}{\sin (90+53)}$

$\frac{200}{1}=\frac{\mathrm{T}_{1}}{\cos 53}$

$\mathrm{T}_{1}=40 \times 3=\mathrm{Kx} \quad \mathrm{K}=3000 \mathrm{N} / \mathrm{m}$

Standard 11

Physics

Share

Similar Questions

For the system shown in figure, $m_1>m_2>m_3 >m_4$ . Initially, the system is at rest in equilibrium condition. If the string joining $m_4$ and ground is cut, then just after the string is cut :
Statement $I$ $m_1$ ,$m_2$ ,$m_3$ remain stationary.
Statement $II$ The value of acceleration of all the $4$ blocks can be determined.
Statement $III$ Only $m_4$ remains stationary.
Statement $IV$ Only $m_4$ accelerates.
Statement $V$ All the four blocks remain stationary.
Now, choose the correct option.

hard

One end of a massless spring of spring constant $k$ and natural length $l_{0}$ is fixed while the other end is connected to a small object of mass $m$ lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity $\omega$ about an axis passing through fixed end, then the elongation of the spring will be

medium

(JEE MAIN-2020)

A body of mass $m$ is tied to one end of a spring and whirled round in a horizontal plane with a constant angular velocity. The elongation in the spring is $1\, cm$. If the angular velocity is doubled, the elongation in the spring is $5\, cm$. The original length of the spring is ……… $cm$

hard

(JEE MAIN-2013)

A body of mass $200\,g$ is tied to a spring of spring constant $12.5\,N / m$, while the other end of spring is fixed at point $O$. If the body moves about $O$ in a circular path on a smooth horizontal surface with constant angular speed $5\,rad / s$, then the ratio of extension in the spring to its natural length will be :

hard

(JEE MAIN-2023)

A man is standing at a spring platform. Reading of spring balance is $60\, kg$ wt. If man jumps outside platform, then reading of spring balance

easy

(AIIMS-2000)