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4-1.Newton's Laws of Motion
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One end of a massless spring of spring constant $k$ and natural length $l_{0}$ is fixed while the other end is connected to a small object of mass $m$ lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity $\omega$ about an axis passing through fixed end, then the elongation of the spring will be
A$\frac{ k - m \omega^{2} l_{0}}{ m \omega^{2}}$
B$\frac{ m \omega^{2} l_{0}}{ k + m \omega^{2}}$
C$\frac{ m \omega^{2} l_{0}}{ k - m \omega^{2}}$
D$\frac{ k + m \omega^{2}l_{0}}{m \omega^{2}}$
(JEE MAIN-2022) (JEE MAIN-2020)
Solution

$K \Delta x = m \ell_{0} w ^{2}+ mw ^{2} \Delta x$
$\Delta x =\frac{ m \ell_{0} w ^{2}}{ k – mw ^{2}}$
Standard 11
Physics
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