Gujarati
Hindi
14.Waves and Sound
normal

In the standing wave shown, particles at the positions $A$ and $B$ have a phase difference of

A

$0$

B

$\frac{\pi }{2}$

C

$\frac{5\pi }{6}$

D

$\pi $

Solution

Phase difference $(\phi)$

$\phi=\frac{3 \pi}{2}-\frac{\pi}{2}$

$\phi=\pi$

Standard 11
Physics

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