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5.Magnetism and Matter
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In two separate experiments the neutral points due to two small magnets are at a distance of $r$ and $ 2r$ n broad side-on position. The ratio of their magnetic moments will be
A
$4:1$
B
$1:2$
C
$2:1$
D
$1:8$
Solution
(d)At broad side-on position $B = \frac{M}{{{d^3}}}$
$\therefore \,\frac{{{M_1}}}{{d_1^3}} = \frac{{{M_2}}}{{d_2^3}}or\frac{{{M_1}}}{{{r^3}}} = \frac{{{M_2}}}{{8{r^3}}}or\frac{{{M_1}}}{{{M_2}}} = \frac{{{r^3}}}{{8{r^3}}} = \frac{1}{8}$
Standard 12
Physics
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