Ionization potential of hydrogen atom is 13.6 V . Hydrogen atoms in ground state are excited by mono

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12.Atoms

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Ionization potential of hydrogen atom is $13.6 V$. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 eV.$ The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

A

$1$

B

$2$

C

$3$

D

$4$

Solution

(c) Final energy of electron $ = – 13.6 + 12.1 = – 1.51eV$ which is corresponds to third level $i.e.\,\,n=3$.

Hence number of spectral lines emitted $=\frac{n(n-1)}{2}=\frac{3(3-1)}{2}=3$

Standard 12

Physics

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