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10-1.Thermometry, Thermal Expansion and Calorimetry
easy
Latent heat of $1\,gm $ of steam is $536 \,cal/gm,$ then its value in $joule/kg$ is
A
$2.25 \times {10^6}$
B
$2.25 \times {10^3}$
C
$2.25$
D
None
Solution
(a) $536\frac{{cal}}{{gm}} = \frac{{536 \times 4.2\,J}}{{{{10}^{ – 3}}\,kg}} = 2.25 \times {10^6}\,J/kg$
Standard 11
Physics
Similar Questions
Match the followings :
| Column $-I$ | Column $-II$ |
| $(a)$ Combined existence of liquid-gaseous state of substance. | $(i)$ Sublimation curve |
| $(b)$ Combined existence of solid-gaseous state of substance. | $(ii)$ Fusion curve |
| $(iii)$ Vaporization curve |
easy
