Let ${\left( {x + 10} \right)^{50}} + {\left( {x - 10} \right)^{50}} = {a_0} + {a_1}x + {a_2}{x^2} + .... + {a_{50}}{x^{50}}$ , for $x \in R$; then $\frac{{{a_2}}}{{{a_0}}}$ is equal to

  • [JEE MAIN 2019]
  • A

    $12.50$

  • B

    $12$

  • C

    $12.25$

  • D

    $12.75$

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