Let left| {{{vec A}_1}} right| = 3,,left | vedclass

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Question

$\begin{array}{l}
\left| {{{\vec A}_1}} ight| = 3,\left| {{{\vec A}_2}} ight| = 5,\,and\,\left| {{{\vec A}_1} + {{\vec A}_2}} ight| = 5.\
\le

Vedclass · Accepted Answer

$-118.5$

Vedclass · Answer

$\begin{array}{l}
\left| {{{\vec A}_1}} ight| = 3,\left| {{{\vec A}_2}} ight| = 5,\,and\,\left| {{{\vec A}_1} + {{\vec A}_2}} ight| = 5.\
\left| {{{\vec A}_1} + {{\vec A}_2}} ight| = {\left| {{{\vec A}_1}} ight|^2} + {\left| {{{\vec A}_2}} ight|^2} + 2\left| {{{\vec A}_1}} ight|\left| {{{\vec A}_2}} ight|\,\cos \,	heta \
\cos \,	heta \, =  - \frac{3}{{10}}\
\left( {2{{\vec A}_1} + 3{{\vec A}_2}} ight).\left( {3{{\vec A}_1} - 2{{\vec A}_2}} ight)\
 = 6{\left| {{{\vec A}_1}} ight|^2} + 9{{\vec A}_1}.{{\vec A}_2} - 4{{\vec A}_1}.{{\vec A}_2} - 6{\left| {{{\vec A}_2}} ight|^2}\
 =  - 118.5
\end{array}$

Colum $I$	Colum $II$
$(A)$ $x-$axis	$(p)$ $5\,unit$
$(B)$ Along another vector $(2 \hat{ i }+\hat{ j }+2 \hat{ k })$	$(q)$ $4\,unit$
$(C)$ Along $(6 \hat{ i }+8 \hat{ j }-10 \hat{ k })$	$(r)$ $0$
$(D)$ Along another vector $(-3 \hat{ i }-4 \hat{ j }+5 \hat{ k })$	$(s)$ None

Let $\left| {{{\vec A}_1}} \right| = 3,\,\left| {\vec A_2} \right| = 5$, and $\left| {{{\vec A}_1} + {{\vec A}_2}} \right| = 5$. The value of $\left( {2{{\vec A}_1} + 3{{\vec A}_2}} \right)\cdot \left( {3{{\vec A}_1} - 2{{\vec A}_2}} \right)$ is

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