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3 and 4 .Determinants and Matrices
medium
Let $A=\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$ and $B=\left[\begin{array}{ccc}9^{2} & -10^{2} & 11^{2} \\ 12^{2} & 13^{2} & -14^{2} \\ -15^{2} & 16^{2} & 17^{2}\end{array}\right]$, then the value of $A ^{\prime} BA$ is.
A
$1224$
B
$1042$
C
$540$
D
$539$
(JEE MAIN-2022)
Solution
$A ^{\prime} BA =\left[\begin{array}{lll}1 & 1 & 1\end{array}\right]\left[\begin{array}{lrc}9^{2} & -10^{2} & 11^{2} \\ 12^{2} & 13^{2} & -14^{2} \\ -15^{2} & 16^{2} & 17^{2}\end{array}\right]\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$
$=\left[\begin{array}{lll}9^{2}+12^{2}-15^{2} & -10^{2}+13^{2}+16^{2} & 11^{2}-14^{2}+17^{2}\end{array}\right]$
$\left[\begin{array}{l}1 \\ 1 \\ 1\end{array}\right]$
$=\left[9^{2}+12^{2}-15^{2}-10^{2}+13^{2}+16^{2}+11^{2}-14^{2}+17^{2}\right]$
$=[539]$
Standard 12
Mathematics