Let overrightarrow C = overrightarrow A + ove | vedclass

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Question

(b) $\vec C + \vec A = \vec B$. 

The value of $C$ lies between $A - B$ and $A + B$

$|\vec C|\; < \;|\vec A|\;\;{\rm{or}}\;\;|\vec C|\; &

Vedclass · Accepted Answer

It is possible to have $|\overrightarrow C |\, < \,|\overrightarrow A |$ and $|\overrightarrow C |\, < \,|\overrightarrow B |$

Vedclass · Answer

(b) $\vec C + \vec A = \vec B$. 

The value of $C$ lies between $A - B$ and $A + B$

$|\vec C|\; < \;|\vec A|\;\;{\rm{or}}\;\;|\vec C|\; < \;|\vec B|$

Let $\overrightarrow C = \overrightarrow A + \overrightarrow B $ then

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