6.Permutation and Combination
normal

Let $n(A) = 3, \,n(B) = 3$ (where $n(S)$ denotes number of elements in set $S$), then number of subsets of $(A \times B)$ having odd number of elements, is-

A

$64$

B

$128$

C

$256$

D

$512$

Solution

$\mathrm{n}(\mathrm{A} \times \mathrm{B})=9$

${\,^9}{{\rm{C}}_1} + {\,^9}{{\rm{C}}_3} +  \ldots  \ldots  + {\,^9}{{\rm{C}}_9} = {2^8} = 256$

Standard 11
Mathematics

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