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Let us cell a motion, $A$ when velocity is positive and increasing $A^{-1}$ when velocity is negative and increasing. $R$ when velocity is positive and decreasing and $R^{-1}$ when velocity is negative and decreasing. Now, match the following two columns for the given $s=t$ graph.
Colum $I$ | Colum $II$ |
$(A)$ $M$ | $(p)$ $A^{-1}$ |
$(B)$ $N$ | $(q)$ $R^{-1}$ |
$(C)$ $P$ | $(r)$ $A$ |
$(D)$ $Q$ | $(s)$ $R$ |

$( A \rightarrow r , B \rightarrow s , C \rightarrow p , D \rightarrow q )$
$( A \rightarrow p , B \rightarrow s , C \rightarrow r , D \rightarrow q )$
$( A \rightarrow r , B \rightarrow p , C \rightarrow s , D \rightarrow q )$
$( A \rightarrow q , B \rightarrow s , C \rightarrow p , D \rightarrow r )$
Solution
(a)
In motion $M$ Slope of $s-t$ graph is positive and increasing. Therefore, velocity of the particle is positive and increasing. Hence, it is $A$ type motion. Similarly, $N, P$ and $Q$ can be observed from the slope.