Gujarati
Hindi
2.Motion in Straight Line
normal

Let us cell a motion, $A$ when velocity is positive and increasing $A^{-1}$ when velocity is negative and increasing. $R$ when velocity is positive and decreasing and $R^{-1}$ when velocity is negative and decreasing. Now, match the following two columns for the given $s=t$ graph.

Colum $I$ Colum $II$
$(A)$ $M$ $(p)$ $A^{-1}$
$(B)$ $N$ $(q)$ $R^{-1}$
$(C)$ $P$ $(r)$ $A$
$(D)$ $Q$ $(s)$ $R$

A

$( A \rightarrow r , B \rightarrow s , C \rightarrow p , D \rightarrow q )$

B

$( A \rightarrow p , B \rightarrow s , C \rightarrow r , D \rightarrow q )$

C

$( A \rightarrow r , B \rightarrow p , C \rightarrow s , D \rightarrow q )$

D

$( A \rightarrow q , B \rightarrow s , C \rightarrow p , D \rightarrow r )$

Solution

(a)

In motion $M$ Slope of $s-t$ graph is positive and increasing. Therefore, velocity of the particle is positive and increasing. Hence, it is $A$ type motion. Similarly, $N, P$ and $Q$ can be observed from the slope.

Standard 11
Physics

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