Position of a particle moving along y- axis is given as y = 3t^2 -t^3 where y is in metre and t is i

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2.Motion in Straight Line

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The position of a particle moving along the $y-$ axis is given as $y = 3t^2 -t^3$ where $y$ is in $metre$ and $t$ is in $second$ . The time when the particle attains maximum positive position will be........$s$

A

$1.5$

B

$4$

C

$2$

D

$3$

Solution

$y=3 t^{2}-t^{3} \Rightarrow \frac{d y}{d t}=6 t-3 t^{2}=0$

at $t=0 ; y=0$

at $t=2, y=4$

Standard 11

Physics

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