- Home
- Standard 12
- Physics
13.Nuclei
medium
Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of
A
$4: 3$
B
$\left(\frac{3}{4}\right)^{\frac{1}{3}}$
C
$1: 1$
D
$\left(\frac{4}{3}\right)^{\frac{1}{3}}$
(JEE MAIN-2022)
Solution
Radius of nucleus $R=R_{0} A^{\frac{1}{3}}$
Density of nucleus $=\frac{\text { Mass of nucleus }}{\text { volume of nucleus }}$
$\rho=\frac{ m \times A }{\frac{4}{3} \pi R ^{3}}$ Where $m :$ mass of proton or neutron
$\rho=\frac{ m \times A }{\frac{4}{3} \pi R _{0}{ }^{3} A }$
$\rho \propto A^{0}$
Hence density of nucleus is independent of mass number
Standard 12
Physics
