Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of
$4: 3$
$\left(\frac{3}{4}\right)^{\frac{1}{3}}$
$1: 1$
$\left(\frac{4}{3}\right)^{\frac{1}{3}}$
A reaction between a proton and $_8{O^{18}}$ that produces $_9{F^{18}}$ must also liberate
Explain by illustrating the types of atoms.
Atomic weight of boron is $10.81$ and it has two isotopes $_5{B^{10}}$ and $_5{B^{11}}$. Then ratio of $ _5{B^{10}}{\,:\,_5}{B^{11}} $ in nature would be
Two nuclei have their mass numbers in the ratio of $1 : 3.$ The ratio of their nuclear densities would be
Two protons exerts a nuclear force on each other, the distance between them is