Mechanism of a hypothetical reaction
$X_2 + Y_2 \rightarrow 2XY,$ is given below :
$(i)\,\, X_2 \rightarrow X + X\, (fast)$
$(ii)\,\,X + Y_2 \rightleftharpoons XY + Y\, (slow)$
$(iii)\,\,X + Y \rightarrow XY\, (fast)$
The overall order of the reaction will be
$2$
$0$
$1.5$
$1$
A student has studied the decomposition of a gas $AB _3$ at $25^{\circ} C$. He obtained the following data.
$p ( mm Hg )$ | $50$ | $100$ | $200$ | $400$ |
Relative $t _{1 / 2}( s )$ | $4$ | $2$ | $1$ | $0.5$ |
The order of the reaction is
The reaction between $A$ and $B$ is first order with respect to $A$ and zero order with respect to $B$. Fill in the blanks in the following table:
Experiment | $[ A ] / mol\, ^{-1}$ | $[ B ] / mol\, ^{-1}$ | Initial rate $/$ $mol$ $L^{-1}$ $min$ $^{-1}$ |
$I$ | $0.1$ | $0.1$ | $2.0 \times 10^{-2}$ |
$II$ | - | $0.2$ | $4.0 \times 10^{-2}$ |
$III$ | $0.4$ | $0.4$ | - |
$IV$ | - | $0.2$ | $2.0 \times 10^{-2}$ |
Consider the data given below for hypothetical reaction $A \to X$
$Time (sec)$ Rate $(mol\, L^{-1} sec.^{-1})$
$0$ $1.60 \times 10^{-2}$
$10$ $1.60 \times 10^{-2}$
$20$ $1.60 \times 10^{-2}$
$30$ $1.60 \times 10^{-2}$
From the above data, the order of reaction is
For a reaction $A \to B$, the rate of reaction quadrupled when the concentration of $A$ is doubled. The rate expression of the reaction is $r = K{(A)^n}$. when the value of $n$ is
For reaction
$X_2(g) + Y_2(g) \rightarrow 2XY (g)$
The following data are observed
$[X_2]$ | $[Y_2]$ | Rate of appearance of $XY$ ($M/sec$) |
$0.1$ | $0.1$ | $5 × 10^{-6}$ |
$0.2$ | $0.1$ | $10^{-5}$ |
$0.2$ | $0.2$ | $4 × 10^{-5}$ |
Rate constant of reaction will (in $M^{1-n}\,sec^{-1}$) where $'n'$ is order of reaction