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7.Profit and Loss
medium
Nisha bought a number of oranges at $2$ for a rupee and an equal number at $3$ for a rupee. To make a profit of $20 \%$ she should sell a dozen for (in $Rs.$)
A
$6$
B
$8$
C
$10$
D
$12$
Solution
Let she bought $60$ oranges of each type
$C.P.$ of type $1$ orange $=0.5 \times 1 / 2$
Total cost price of type $1$ orange $=0.5 \times 1 / 2 \times 60$
$=30$
Total $C.P.$ of type $2$ orange $=1 / 3 \times 60=20$
$C.P.$ $=30+20=50$
Profit $=\frac{20}{100} \times 50=10$
Total $S.P.$ $50+10=60$
Now, this $S.P.$ is for $120$ oranges
For $12$ oranges, $S.P. =12 \times \frac{60}{120}=6$
Standard 13
Quantitative Aptitude
