1. Electric Charges and Fields
easy

Number of electrons in one coulomb of charge will be

A

$5.46 \times {10^{29}}$

B

$6.25 \times {10^{18}}$

C

$1.6 \times {10^{ + 19}}$

D

$9 \times {10^{11}}$

(AIIMS-1999)

Solution

(b) $n = \frac{q}{e} = \frac{1}{{1.6 \times {{10}^{ – 19}}}} = 6.25 \times {10^{18}}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.