Obtain scalar product of two mutually perpendicular vectors.

English

Gujarati

Hindi

3-1.Vectors

easy

Obtain the scalar product of two mutually perpendicular vectors.

Option A

Option B

Option C

Option D

Solution

$\text { If } \vec{A} \perp \vec{B}, \text { then } \theta=90^{\circ}$

$\therefore \quad \vec{A} \cdot \vec{B}=\mathrm{ABcos} 90^{\circ}$

$=0$

$\because \cos 90^{\circ}=0$

This is the condition for mutually perpendicular of two non-zero vectors.

Standard 11

Physics

Share

Similar Questions

Explain the kinds of multiplication operations for vectors.

medium

The angle between the two vectors $\vec A = 3\hat i + 4\hat j + 5\hat k$ and $\vec B = 3\hat i + 4\hat j – 5\hat k$ will be……. $^o$

medium

(AIPMT-1994)

The component of vector $A = 2\hat i + 3\hat j$ along the vector $\hat i + \hat j$is

medium

If $| A |=2,| B |=5$ and $| A \times B |=8$ Angle between $A$ and $B$ is acute, then $A \cdot B$ is

easy

A vector $\vec{A}$ points towards North and vector $\vec{B}$ points upwards then $\vec{A} \times \vec{B}$ points towards ………..

easy