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7.Gravitation
normal
The escape velocity from a planet is $V_e.$ A tunnel is dug along the diameter of the planet and a small body dropped into it. The speed of the body at the centre of the planet will be
A
$\frac {V_e}{\sqrt 2}$
B
$\frac {V_e}{2}$
C
$V_e$
D
$2V_e$
Solution
Energy conservation
$-\frac{\mathrm{GMm}}{\mathrm{R}}+0=-\frac{3}{2} \frac{\mathrm{GMm}}{\mathrm{R}}+\frac{1}{2} \mathrm{mV}^{2}$
$\mathrm{V}_{\mathrm{e}}=\sqrt{\frac{2 \mathrm{GM}}{\mathrm{R}}}$ so $\mathrm{V}=\frac{\mathrm{V}_{\mathrm{e}}}{\sqrt{2}}$
Standard 11
Physics