Gujarati
Hindi
12.Kinetic Theory of Gases
normal

On the basis of kinetic theory of gases, the mean $K.E.$ of $1\,\, mole$ per degree of freedom is

A

$\frac {1}{2}\,\, RT$

B

$\frac {3}{2}\,\, RT$

C

$\frac {1}{2}\,\, kT$

D

$\frac {3}{2}\,\, kT$

Solution

$\frac{1}{2}kT\, \times \,N\, = \,\frac{1}{2}RT$

Standard 11
Physics

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