4-2.Friction
medium

On the horizontal surface of a truck a block of mass $1 \;kg$ is placed $(\mu=0.6)$ and truck is moving with acceleration $5\; m / sec ^2$ then the frictional force on the block will be

A$5$
B$6$
C$5.88$
D$8$
(AIPMT-2001)

Solution

$(a)$ ${F_l} = \mu mg = 0.6 \times 1 \times 9.8 = 5.88\;N$
Pseudo force on the block = $ma = 1 \times 5 = 5\;N$
Pseudo is less then limiting friction hence static force of friction $= 5\, N.$
Standard 11
Physics

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