One gm mol of a diatomic gas (gamma = 1.4) is compressed adiabatically so that its temperature rises

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11.Thermodynamics

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One gm mol of a diatomic gas $(\gamma = 1.4)$ is compressed adiabatically so that its temperature rises from ${27^o}C$ to ${127^o}C$. The work done will be

A

$2077.5\, joules$

B

$207.5\, joules$

C

$207.5 \,ergs$

D

None of the above

Solution

(a) $W = \frac{R}{{\gamma – 1}}({T_1} – {T_2})$
$ = \frac{{8.31 \times \{ (273 + 27) – (273 + 127)\} }}{{1.4 – 1}} = – 2077.5\;joules$

Standard 11

Physics

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