Out of 9 persons , 8 persons spent Rs., 30 each for their meals. nineth one spent Rs., 20 more then

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4.Average

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Out of $9$ persons$, 8$ persons spent $Rs.\, 30$ each for their meals. The nineth one spent $Rs.\, 20$ more then the average expenditure of all the nine. The total money spent by all of them was (in $Rs.$)

A

$260$

B

$290$

C

$292.50$

D

$400.50$

Solution

Let the total money spent be $x$

$\therefore$ Average expenditure $=Rs.\, \frac{x}{9}$

$\therefore \quad 8 \times 30+\left(\frac{x}{9}+20\right)=x$

$260=x-\frac{x}{9}$

$260=\frac{8 x}{9}$

$x=\frac{260 \times 9}{8}=32.5 \times 9=Rs.\, 292.5$

Standard 13

Quantitative Aptitude

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