p-Block Elements - I
easy

Outermost electronic configuration of a group $13$ element, $E$, is $4 \,\mathrm{~s}^{2}, 4 p^{1}$. The electronic configuration of an element of $p$-block period-five placed diagonally to element, $E$ is :

A

$[\mathrm{Xe}]{5} \mathrm{~d}^{10} 6 \mathrm{~s}^{2} 6 \mathrm{p}^{2}$

B

$[\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^{2} 5 \mathrm{p}^{2}$

C

$[\mathrm{Kr}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{2} 4 \mathrm{p}^{2}$

D

$ [Ar]$ $3 d^{10} 4 s^{2} 4 p^{2}$

(JEE MAIN-2021)

Solution

The element $\mathrm{E}$ is $\mathrm{Ga}$ and the diagonal element of $5^{\mathrm{th}}$ period is ${ }_{50} \mathrm{Sn}$ having outer electronic configuration will be $[\mathrm{Kr}] \,5 \mathrm{~s}^{2} \,4 \mathrm{~d}^{10}\, 5 \mathrm{p}^{2}$.

Standard 11
Chemistry

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