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6.System of Particles and Rotational Motion
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Part of the tuning arrangement of a radio consists of a wheel which is acted on by two parallel constant forces as shown in the fig. If the wheel rotates just once, the work done will be about (diameter of the wheel = $0.05\ m$)
A
$0.062\ J$
B
$0.031\ J$
C
$0.015\ J$
D
$0.057\ J$
Solution
Rotational kinetic energy $\frac{1}{2}I{\omega ^2}$
$= \frac{1}{2}\left( {\frac{1}{2}M{R^2}} \right)\,{\omega ^2}$
$ = \frac{1}{2}\left( {\frac{1}{2} \times 10 \times {{(0.5)}^2}} \right)\,{\left( {20} \right)^2}$
$= 250\,J$
Standard 11
Physics
