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6.System of Particles and Rotational Motion
medium
An automobile engine develops $100\ kW$ when rotating at a speed of $1800\ rev/min$. What torque does it deliver .......... $N-m$
A
$350$
B
$440$
C
$531$
D
$628$
Solution
$P = \tau \omega $
$⇒$ $\tau = \frac{{100 \times {{10}^3}}}{{2\pi \,\frac{{1800}}{{60}}}} $
$= 531\,N{\rm{ – }}m$
Standard 11
Physics