6.System of Particles and Rotational Motion
medium

An automobile engine develops $100\ kW$ when rotating at a speed of $1800\ rev/min$.  What torque does it deliver .......... $N-m$

A

$350$

B

$440$

C

$531$

D

$628$

Solution

$P = \tau \omega $

$⇒$ $\tau  = \frac{{100 \times {{10}^3}}}{{2\pi \,\frac{{1800}}{{60}}}} $

$= 531\,N{\rm{ –  }}m$

Standard 11
Physics

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