Radius of _2H{e^4} nucleus is 3 ,Fermi. The r | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) We have $r \propto {A^{1/3}} \Rightarrow \frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{A_2}}}{{{A_1}}}} \right)^{1/3}} = {\left( {\frac{{206}}{4}} \r

Vedclass · Accepted Answer

$11.16$

Vedclass · Answer

(c) We have $r \propto {A^{1/3}} \Rightarrow \frac{{{r_2}}}{{{r_1}}} = {\left( {\frac{{{A_2}}}{{{A_1}}}} ight)^{1/3}} = {\left( {\frac{{206}}{4}} ight)^{1/3}}$

$	herefore {r_2} = 3{\left( {\frac{{206}}{4}} ight)^{1/3}} = 11.6\;Fermi$.

Radius of $_2H{e^4}$ nucleus is $3 \,Fermi.$ The radius of $_{82}P{b^{206}}$ nucleus will be..........$fermi$

Similar Questions

The mass of an $\alpha$-particle is

Antiparticle of electron is

The increasing order of atomic radii of the following Group $13$ elements is

Which of the following pairs is an isobar

$\pi $ mesons can be