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4-1.Newton's Laws of Motion
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Radius of the curved road on national highway is $R$. Width of the road is $b$. The outer edge of the road is raised by $h$ with respect to inner edge so that a car with velocity $v$ can pass safe over it. The value of $h$ is
A$\frac{{{v^2}b}}{{Rg}}$
B$\frac{v}{{Rgb}}$
C$\frac{{{v^2}R}}{g}$
D$\frac{{{v^2}b}}{R}$
Solution
(a) We know that $\tan \theta = \frac{{{v^2}}}{{Rg}}$ and $\tan \theta = \frac{h}{b}$
Hence $\frac{h}{b} = \frac{{{v^2}}}{{Rg}}$
$⇒$ $h = \frac{{{v^2}b}}{{Rg}}$
Hence $\frac{h}{b} = \frac{{{v^2}}}{{Rg}}$
$⇒$ $h = \frac{{{v^2}b}}{{Rg}}$
Standard 11
Physics
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