A motor cycle driver doubles its velocity when he is having a turn. force exerted outwardly will be

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4-1.Newton's Laws of Motion

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A motor cycle driver doubles its velocity when he is having a turn. The force exerted outwardly will be

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C$4$ times

D$\frac{1}{4}$ times

Solution

(c) $F = \frac{{m{v^2}}}{r}$ $⇒$ $F \propto {v^2}$ i.e. force will become $4$ times.

Standard 11

Physics

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