Range of a bullet fired at 45^o to horizontal is 980m . If bullet is fired at same angle

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3-2.Motion in Plane

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Range of a bullet fired at $45^o$ to horizontal is $980m$. If the bullet is fired at same angle from a car travelling horizontally at $18\, km/hr$ towards target then range will be increased by :-

A

$100\, \sqrt 2 \,m$

B

$100\, \sqrt 7 \,m$

C

$50\, \sqrt 2 \,m$

D

$50\, \sqrt 7 \,m$

Solution

$\frac{u^{2}}{g}=980$

$\mathrm{u}=98 \mathrm{m} / \mathrm{s}$

$\mathrm{T}=\frac{2 \times 98}{9.8} \times \frac{1}{\sqrt{2}}=10 \sqrt{2}$ seconds

$18 \mathrm{km} / \mathrm{h}=5 \mathrm{m} / \mathrm{s}$ hence range increase by

$\Delta \mathrm{R}=(\Delta \mathrm{V}) \mathrm{T}=5 \times 10 \sqrt{2}$

Standard 11

Physics

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