Gujarati
Hindi
12.Atoms
normal

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

A

$\frac{9}{{31}}$

B

$\frac{5}{{27}}$

C

$\frac{3}{{23}}$

D

$\frac{7}{{29}}$

Solution

$\left(\frac{\lambda_{\text {Lyman }}}{\lambda_{\text {Balmer }}}\right)_{\max }=\frac{\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)}{\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)}=\frac{5 / 36}{3 / 4}=\frac{5}{27}$

Standard 12
Physics

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