Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

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12.Atoms

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Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

$\frac {9}{31}$

$\frac {5}{27}$

$\frac {3}{23}$

$\frac {7}{29}$

Solution

${\left( {\frac{{{\lambda _{Lyman}}}}{{{\lambda _{Balmer}}}}} \right)_{\max }} = \frac{{\left( {\frac{1}{{{2^2}}} – \frac{1}{{{3^2}}}} \right)}}{{\left( {\frac{1}{{{1^2}}} – \frac{1}{{{2^2}}}} \right)}} = \frac{{5/36}}{{3/4}} = \frac{5}{{27}}$

Standard 12

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Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

Solution

Similar Questions

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