Reaction $2A + B \to$  product,  rate law is $\frac{{ - d[A]}}{{dt}}\, = \,K[A].$ At a time when $t\, = \,\frac{{{t_{1/2}}}}{{\ln\,2}},$ concentration of the reactant is

  • A

    ${[A]_0}e$

  • B

    $\frac{{{{[A]}_0}}}{{{e^2}}}$

  • C

    $\frac{{{{[A]}_0}}}{{{e}}}$

  • D

    $\frac{1}{{{{[A]}_0}}}$

Similar Questions

What is the order of reaction' for $A + B \to C$

Observation $[A]$ $[B]$ Rate of reaction
$1$ $0.1$ $0.1$ $2\times10^{-3}\, mol\, L^{-1}\,sec^{-1}$
$2$ $0.2$ $0.1$ $0.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$
$3$ $0.1$ $0.2$ $1.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$

Write unit of rate constant of following reaction :

$1.$ zero order

$2.$ second order

Order of radioactive disintegration reaction is

The rate law of the reaction $2{N_2}{O_5} \to 4N{O_2} + {O_2}$ is

In a chemical reaction $A$ is converted into $B$ . The rates of reaction, starting with initial concentrations of $A$ as $2 \times {10^{ - 3}}\,M$ and $1 \times {10^{ - 3}}\,M$ , are equal to $2.40 \times {10^{ - 4}}\,M{s^{ - 1}}$ and $0.60 \times {10^{ - 4}}\,M{s^{ - 1}}$ respectively. The order of reaction with respect to reactant $A$ will be

  • [AIEEE 2012]