Reaction $2A + B \to$ product, rate law is $\frac{{ - d[A]}}{{dt}}\, = \,K[A].$ At a time when $t\, = \,\frac{{{t_{1/2}}}}{{\ln\,2}},$ concentration of the reactant is
${[A]_0}e$
$\frac{{{{[A]}_0}}}{{{e^2}}}$
$\frac{{{{[A]}_0}}}{{{e}}}$
$\frac{1}{{{{[A]}_0}}}$
What is the order of reaction' for $A + B \to C$
Observation | $[A]$ | $[B]$ | Rate of reaction |
$1$ | $0.1$ | $0.1$ | $2\times10^{-3}\, mol\, L^{-1}\,sec^{-1}$ |
$2$ | $0.2$ | $0.1$ | $0.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
$3$ | $0.1$ | $0.2$ | $1.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
Write unit of rate constant of following reaction :
$1.$ zero order
$2.$ second order
Order of radioactive disintegration reaction is
The rate law of the reaction $2{N_2}{O_5} \to 4N{O_2} + {O_2}$ is
In a chemical reaction $A$ is converted into $B$ . The rates of reaction, starting with initial concentrations of $A$ as $2 \times {10^{ - 3}}\,M$ and $1 \times {10^{ - 3}}\,M$ , are equal to $2.40 \times {10^{ - 4}}\,M{s^{ - 1}}$ and $0.60 \times {10^{ - 4}}\,M{s^{ - 1}}$ respectively. The order of reaction with respect to reactant $A$ will be