Write unit of rate constant of following reaction :

$1.$ zero order

$2.$ second order

The reaction $CH _{3} COF + H _{2} O \quad \rightleftharpoons CH _{3} COOH + HF$

Condition $I$ $:$ $\left[ H _{2} O \right]_{0}=1.00 \,M$

                           $\left[ CH _{3} COF \right]_{0}=0.01 \,M$

Condition $II$ $:$ $\left[ H _{2} O \right]_{0}=0.02 \,M$

                             $\left[ CH _{3} COF \right]_{0}=0.80 \,M$

Determine the order of reaction and calculate rate constant.

The variation of the rate of an enzyme catalyzed reaction with substrate concentration is correctly represented by graph

The reaction, ${N_2}{O_5} \longrightarrow 2NO + \frac{1}{2}\,{O_2}$ is of first order for $N_2O_5$ with rate constant $6.2 \times 10^{-4}\, s^{-1}$. what is the value of rate of reaction when $[N_2O_5] = 1.25\, mol\, L^{-1}$

The data for the reaction $A + B \to C$ is

The rate law of the reaction $A + 2B \to $Product is given by $\frac{{d[dB]}}{{dt}} = k[{B^2}]$. If $ A$  is taken in excess, the order of the reaction will be