Relation between velocity and displacement is v = x^2 . Find acceleration at x = 3m :- .............

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2.Motion in Straight Line

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Relation between velocity and displacement is $v = x^2$. Find acceleration at $x = 3m$ :- ............. $\mathrm{m/s}^{2}$

A

$6$

B

$27$

C

$54$

D

$0$

Solution

$\mathrm{v}=\mathrm{x}^{2}$

$\frac{\mathrm{dV}}{\mathrm{dx}}=2 \mathrm{x}$

$\frac{\mathrm{vdv}}{\mathrm{dx}}=\mathrm{v} \cdot 2 \mathrm{x}$

$a=2 v x=2 x^{2} x$

${a=2 x^{3}}$

${a=2(3)^{3}}$

${a=54 \mathrm{m} / \mathrm{s}^{2}}$

Standard 11

Physics

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