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Question

Let the rate law be $r\,=\,k\,[A]^x[B]^y$

Divide $(3)$ by $(1)$ $\frac{{0.10}}{{0.10}}{\mkern 1mu} \, = \,{\mkern 1mu} \frac{{{{[0.024]}^x}{{[0.035

Vedclass · Accepted Answer

Rate $= k[B]^3$

Vedclass · Answer

Let the rate law be $r\,=\,k\,[A]^x[B]^y$

Divide $(3)$ by $(1)$ $\frac{{0.10}}{{0.10}}{\mkern 1mu} \, = \,{\mkern 1mu} \frac{{{{[0.024]}^x}{{[0.035]}^y}}}{{{{[0.012]}^x}{{[0.035]}^y}}}$

$	herefore \,1\, = \,{[2]^x},\,x\, = \,0$

Divide $(2)$ by $(3)$ 

$\frac{{0.80}}{{0.10}}{\mkern 1mu} \, = \,{\mkern 1mu} \frac{{{{[0.024]}^x}{{[0.070]}^y}}}{{{{[0.024]}^x}{{[0.035]}^y}}}$

$	herefore $ $8 = \,{(2)^y},\,y\, = \,3$

Hence rate equation ,

$R\,=\,k[A]^0\,[B]^3$ $=\,k[B]^3$

Expt. No.	$(A)$	$(B)$	Initial Rate
$1$	$0.012$	$0.035$	$0.10$
$2$	$0.024$	$0.070$	$0.80$
$3$	$0.024$	$0.035$	$0.10$
$4$	$0.012$	$0.070$	$0.80$

Select the rate law that corresponds to the data shown for the following reaction $A+ B\to C$

Expt. No. $(A)$ $(B)$ Initial Rate

$1$ $0.012$ $0.035$ $0.10$

$2$ $0.024$ $0.070$ $0.80$

$3$
$0.024$
$0.035$ $0.10$

$4$ $0.012$ $0.070$ $0.80$

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Select the rate law that corresponds to the data shown for the following reaction $A+ B\to C$ Expt. No. $(A)$ $(B)$ Initial Rate $1$ $0.012$ $0.035$ $0.10$ $2$ $0.024$ $0.070$ $0.80$ $3$ $0.024$ $0.035$ $0.10$ $4$ $0.012$ $0.070$ $0.80$