Six charges are placed at corner of a regular hexagon as shown. If an electron is placed at its cent

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1. Electric Charges and Fields

normal

Six charges are placed at the corner of a regular hexagon as shown. If an electron is placed at its centre $O$, force on it will be:

Zero

Along $OF$

Along $OC$

None of these

Solution

The charges will be balanced by their counterparts on opposite side. So eventually the charges remaining will be $2 q$ on $\mathrm{B}$ and $3 q$ on $\mathrm{D}$.

since the charge distribution is unsymmetrical, the net force on charge would be skewed towards $D.$

Standard 12

Physics

How did Coulomb find the law of value of electric force between two point charges ?

hard

The law, governing the force between electric charges is known as

easy

Assertion : A deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ be the forces acting on them and $a_1$ and $a_2$ be their accelerations respectively then, $a_1 = a_2$.

Reason : Forces will be same in electric field

medium

(AIIMS-2015)

The force between two charges $0.06\,m$ apart is $5\,N$. If each charge is moved towards the other by $0.01\,m$, then the force between them will become………$N$

easy

The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance $5 \times {10^{ – 11}}\,m,$ will be (Charge on electron $=$ $1.6 \times 10^{-19}$ $C$, mass of electron = $ 9.1 \times 10^{-31}$ $kg$, mass of proton = $1.6 \times {10^{ – 27}}\,kg,$ $\,G = 6.7 \times {10^{ – 11}}\,N{m^2}/k{g^2})$