Six moles of an ideal gas performs a cycle sh | vedclass

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Question

Given, $n=6$

$\mathrm{AB}:$ isochoric process, $\Delta W_{A B}=0$

$\mathrm{BC}:$ isobaric process, $\Delta W_{B C}=n R \Delta T$

$=n R\left(T

Vedclass · Accepted Answer

$40$

Vedclass · Answer

Given, $n=6$

$\mathrm{AB}:$ isochoric process, $\Delta W_{A B}=0$

$\mathrm{BC}:$ isobaric process, $\Delta W_{B C}=n R \Delta T$

$=n R\left(T_{c}-T_{a}ight)$

$=6 R(2200-800)$

$=8400 R$

$CD:$isochoric process, $\Delta W_{C D}=0$

$DA:$ isobaric process, $\Delta W_{D A}=n R \Delta T$

$=n R\left(T_{A}-T_{D}ight)$

$=6 R(600-1200)$

$=-3600 R$

$\Delta W_{	ext {cyclic }}=\Delta W_{A a}+\Delta W_{a c}+\Delta W_{C o}+\Delta W_{D A}$

$=8400 R-3600 R=4800 R$

$=4800 	imes 8.3$

$=39840 J \equiv 40 \mathrm{kJ}$

Six moles of an ideal gas performs a cycle shown in figure. If the temperature are $T_A = 600\,K,\,\,T_B = 800\,K,\,\,T_C = 2200\,K$ and $T_D = 1200\,K,$ the work done per cycle is...... $kJ$

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