Six points are there on a circle . Two triangles are drawn with no vertex common. probability that n

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14.Probability

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Six points are there on a circle . Two triangles are drawn with no vertex common. What is the probability that none of the sides of the triangles intersect

A

$\frac{2}{5}$

B

$\frac{1}{3}$

C

$\frac{7}{20}$

D

$\frac{3}{10}$

Solution

Let the points be $A_1 , A_2 …… A_6$

probability is $\frac{6}{{{}^{6{C_3}}}} = \frac{3}{{10}}$

Standard 11

Mathematics

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