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14.Probability
easy
A bag contains $3$ red, $4$ white and $5$ black balls. Three balls are drawn at random. The probability of being their different colours is
A
$\frac{3}{{11}}$
B
$\frac{2}{{11}}$
C
$\frac{8}{{11}}$
D
None of these
Solution
(a) Probability $ = \frac{{^3{C_1}{.^4}{C_1}{.^5}{C_1}}}{{^{12}{C_3}}}$$ = \frac{3}{{11}}$.
Standard 11
Mathematics