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6-2.Equilibrium-II (Ionic Equilibrium)
hard
Solubility product of a sulphide $MS$ is $3 \times {10^{ - 25}}$ and that of another sulphide $NS $ is $4 \times {10^{ - 40}}$. In ammoniacal solution
A
Only $NS$ gets precipitated
B
Only $MS $ gets precipitated
C
No sulphide precipitates
D
Both sulphides precipitate
Solution
(d)The concentration of ${S^{2 – }}$ions in group II is lowered by maintaining acidic medium in the presence of $N{H_4}Cl$. The ionization of ${H_2}S$ is supressed due to common ion effect. So the ionic product is less than solubility product.
Standard 11
Chemistry