- Home
- Standard 11
- Physics
10-2.Transmission of Heat
normal
Star$ S_1$ emits maximum radiation of wavelength $420$ $nm$ and the star $S_2$ emits maximum radiation of wavelength $560 \,\,nm$, what is the ratio of the temperature of $S_1$ and $S_2$ :
A
$4/3$
B
$(4/3)^{1/4}$
C
$3/4$
D
$(3/4)^{1/2}$
Solution
Wien's displacement law states that$:$
$\lambda_{m} T=b(\text { constant })$
i.e. $\lambda_{1} T_{S_{1}}=\lambda_{2} T_{S_{2}}$
$\frac{T S_{1}}{T S_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{560}{420}=\frac{4}{3}$
Standard 11
Physics
Similar Questions
normal
normal
normal