Three copper blocks of masses M₁, M₂ and M₃ kg respectively are brought into thermal contact&n

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10-2.Transmission of Heat

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Three copper blocks of masses $M_1, M_2$ and $M_3$ $kg$ respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at $T_1, T_2, T_3(T_1> T_3)$. Assuming there is no heat loss to the surroundings, the equilibrium temprature $T$ is ($s$ is specific heat of copper)

A

$T = \frac{{{T_1} + {T_2} + {T_3}}}{3}$

B

$T = \frac{{{M_1}{T_1} + {M_2}{T_2} + {M_3}{T_3}}}{{{M_1} + {M_2} + {M_3}}}$

C

$T = \frac{{{M_1}{T_1} + {M_2}{T_2} + {M_3}{T_3}}}{{3\left( {{M_1} + {M_2} + {M_3}} \right)}}$

D

$T = \frac{{{M_1}{T_1}S + {M_2}{T_2}S + {M_3}{T_3}S}}{{3\left( {{M_1} + {M_2} + {M_3}} \right)}}$

Solution

$M_1s(T_1 -T) + M_2s (T_2 -T) + M_3s (T_3 -T) = 0$

Standard 11

Physics

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