Starting from rest, acceleration of a particle is a = 2(t - 1). velocity of particle at t = 5,s is..

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2.Motion in Straight Line

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Starting from rest, acceleration of a particle is $a = 2(t - 1).$ The velocity of the particle at $t = 5\,s$ is.........$m/sec$

$15$

$25$

$5$

$3$

(AIIMS-2019)

Solution

(a)$ \Rightarrow dv = 2(t – 1)\;dt$
$ \Rightarrow \nu = \int_0^5 2 \;(t – 1)dt = 2\left[ {\frac{{{t^2}}}{2} – t} \right]_0^5$$ = 2\left[ {\frac{{25}}{2} – 5} \right]$ $ = 15 \,m/s$

Standard 11

Physics

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Starting from rest, acceleration of a particle is $a = 2(t - 1).$ The velocity of the particle at $t = 5\,s$ is.........$m/sec$

Solution

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