Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
- A
Statement$-1$ is True, Statement$-2$ is True; Statement$-2$ is a correct explanation for Statement$-1.$
- B
Statement$-1$ is True, Statement$-2$ is True; Statement$-2$ is NOT a correct explanation for Statement$-1.$
- C
Statement$-1$ is True, Statement$-2$ is False.
- D
Statement$-1$ and Statement$-2$ both are False
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